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Este Cmap, tiene información relacionada con: Ingles b Modelo de Razonamiento de Resolucion de Problemas de Cinematica de un MRUA, <math xmlns="http://www.w3.org/1998/Math/MathML"> <mmultiscripts> <mtext> v </mtext> <mtext> f </mtext> <none/> </mmultiscripts> <mtext> = </mtext> <msqrt> <mtext> 2as </mtext> </msqrt> </math> <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtext> that for free fall, it is </mtext> </math> <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mmultiscripts> <mtext> v </mtext> <mtext> f </mtext> <none/> </mmultiscripts> <mtext> = </mtext> <msqrt> <mtext> 2gh </mtext> </msqrt> </mrow> </math>, <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mmultiscripts> <mtext> v </mtext> <mtext> f </mtext> <none/> </mmultiscripts> <mtext> = </mtext> <msqrt> <mtext> 2gh </mtext> </msqrt> </mrow> </math> where <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> g = 9'81 m/ </mtext> <mmultiscripts> <mtext> s </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> </mrow> </math>, THESE EXAMPLES OF VERTICAL SHOTS ".. is dropped", means that <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mmultiscripts> <mtext> v </mtext> <mtext> 0 </mtext> <none/> </mmultiscripts> <mtext> = 0 </mtext> </mrow> </math>, THIS EXAMPLE has SOLUTION, MATHEMATICAL RELATIONSHIPS (Equations) There are ONLY 2 independent <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> s = </mtext> <mmultiscripts> <mtext> v </mtext> <mtext> 0 </mtext> <none/> </mmultiscripts> <mtext> ⋅t + </mtext> <mfrac> <mtext> 1 </mtext> <mtext> 2 </mtext> </mfrac> <mtext> ⋅a⋅ </mtext> <mmultiscripts> <mtext> t </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> </mrow> </math>, DATA sometimes are not explicit in the statement, as in THESE EXAMPLES OF VERTICAL SHOTS, UNKNOWNS we can only find the value of TWO UNKNOWNS, <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> s = </mtext> <mmultiscripts> <mtext> v </mtext> <mtext> 0 </mtext> <none/> </mmultiscripts> <mtext> ⋅t + </mtext> <mfrac> <mtext> 1 </mtext> <mtext> 2 </mtext> </mfrac> <mtext> ⋅a⋅ </mtext> <mmultiscripts> <mtext> t </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> </mrow> </math> <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> combined and if </mtext> <mmultiscripts> <mtext> v </mtext> <mtext> 0 </mtext> <none/> </mmultiscripts> <mtext> =0, give </mtext> </mrow> </math> <math xmlns="http://www.w3.org/1998/Math/MathML"> <mmultiscripts> <mtext> v </mtext> <mtext> f </mtext> <none/> </mmultiscripts> <mtext> = </mtext> <msqrt> <mtext> 2as </mtext> </msqrt> </math>, MISCONCEPTIONS such as THIS EXAMPLE, <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> s = </mtext> <mmultiscripts> <mtext> v </mtext> <mtext> 0 </mtext> <none/> </mmultiscripts> <mtext> ⋅t + </mtext> <mfrac> <mtext> 1 </mtext> <mtext> 2 </mtext> </mfrac> <mtext> ⋅a⋅ </mtext> <mmultiscripts> <mtext> t </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> </mrow> </math> we can only find the value of TWO UNKNOWNS, <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> s = </mtext> <mmultiscripts> <mtext> v </mtext> <mtext> 0 </mtext> <none/> </mmultiscripts> <mtext> ⋅t + </mtext> <mfrac> <mtext> 1 </mtext> <mtext> 2 </mtext> </mfrac> <mtext> ⋅a⋅ </mtext> <mmultiscripts> <mtext> t </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> </mrow> </math> may be sufficient only ONE EQUATION, TWO UNKNOWNS need to know the value of 3 DATA, 5 VARIABLES are ACCELERATION (a), <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> v </mtext> <mmultiscripts> <mtext> </mtext> <mtext> f </mtext> <none/> </mmultiscripts> <mtext> = v </mtext> <mmultiscripts> <mtext> </mtext> <mtext> 0 </mtext> <none/> </mmultiscripts> <mtext> + a.t </mtext> </mrow> </math> we can only find the value of TWO UNKNOWNS, 5 VARIABLES are TIME (t), <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mmultiscripts> <mtext> v </mtext> <mtext> f </mtext> <none/> </mmultiscripts> <mtext> = </mtext> <msqrt> <mtext> 2gh </mtext> </msqrt> </mrow> </math> could be used NEVER, <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> s = </mtext> <mmultiscripts> <mtext> v </mtext> <mtext> 0 </mtext> <none/> </mmultiscripts> <mtext> ⋅t + </mtext> <mfrac> <mtext> 1 </mtext> <mtext> 2 </mtext> </mfrac> <mtext> ⋅a⋅ </mtext> <mmultiscripts> <mtext> t </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> </mrow> </math> where s is the DISPLACEMENT (NET SPACE TRAVELED) ON THAT t, 5 VARIABLES are <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> FINAL 
VELOCITY ( </mtext> <mmultiscripts> <mtext> v </mtext> <mtext> f </mtext> <none/> </mmultiscripts> <mtext> ) </mtext> </mrow> </math>, 5 VARIABLES those that have unknown values are known as UNKNOWNS, MATHEMATICAL RELATIONSHIPS (Equations) between UNKNOWNS